6) $$\frac{(2^3 \cdot 2^4)^5}{(2 \cdot 2^7)^4}$$

$$\frac{(2^3 \cdot 2^4)^5}{(2 \cdot 2^7)^4} = \frac{(2^{3+4})^5}{(2^{1+7})^4} = \frac{(2^7)^5}{(2^8)^4} = \frac{2^{7 \cdot 5}}{2^{8 \cdot 4}} = \frac{2^{35}}{2^{32}} = 2^{35-32} = 2^3 = 8$$

Ответ: 8