Вопрос:

From point F outside the circle, two secants are drawn. The first secant intersects the circle at points A and B (A between F and B), and the second secant intersects the circle at points C and D (C between F and D). Chords AD and BC intersect at point E. Find the degree measure of angle BED if ∠BFD = 36° and arc AC : arc BD = 2 : 5.

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Ответ:

Analysis of the problem:

We are given a diagram with a circle and two secants drawn from an external point F. The secants intersect the circle at points A, B and C, D respectively. The chords AD and BC intersect inside the circle at point E. We are given the angle ∠BFD = 36° and the ratio of the measures of arcs AC and BD as 2:5.

We need to find the measure of angle BED.

Key Geometric Properties:

  • The angle formed by two secants drawn from an external point to a circle is half the difference of the measures of the intercepted arcs. So, ∠BFD = 1/2 * (arc BD - arc AC).
  • The angle formed by two intersecting chords inside a circle is half the sum of the measures of the intercepted arcs. So, ∠BED = 1/2 * (arc BD + arc AC).

Solution:

  1. Using the external secant angle formula:
    • We are given ∠BFD = 36°.
    • Let the measure of arc AC be 2x and the measure of arc BD be 5x, based on the given ratio.
    • According to the formula for the angle formed by two secants:

    ∠BFD = 1/2 * (m(arc BD) - m(arc AC))

    36° = 1/2 * (5x - 2x)

    36° = 1/2 * (3x)

    72° = 3x

    x = 72° / 3

    x = 24°

  2. Calculate the measures of the arcs:
    • Measure of arc AC = 2x = 2 * 24° = 48°.
    • Measure of arc BD = 5x = 5 * 24° = 120°.
  3. Using the intersecting chords angle formula:
    • Now we need to find ∠BED. The chords AD and BC intersect at E.
    • According to the formula for the angle formed by two intersecting chords:

    ∠BED = 1/2 * (m(arc BD) + m(arc AC))

    ∠BED = 1/2 * (120° + 48°)

    ∠BED = 1/2 * (168°)

    ∠BED = 84°

Final Answer:

Ответ: 84

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