Analysis of the problem:
We are given a diagram with a circle and two secants drawn from an external point F. The secants intersect the circle at points A, B and C, D respectively. The chords AD and BC intersect inside the circle at point E. We are given the angle ∠BFD = 36° and the ratio of the measures of arcs AC and BD as 2:5.
We need to find the measure of angle BED.
Key Geometric Properties:
- The angle formed by two secants drawn from an external point to a circle is half the difference of the measures of the intercepted arcs. So, ∠BFD = 1/2 * (arc BD - arc AC).
- The angle formed by two intersecting chords inside a circle is half the sum of the measures of the intercepted arcs. So, ∠BED = 1/2 * (arc BD + arc AC).
Solution:
- Using the external secant angle formula:
- We are given ∠BFD = 36°.
- Let the measure of arc AC be 2x and the measure of arc BD be 5x, based on the given ratio.
- According to the formula for the angle formed by two secants:
∠BFD = 1/2 * (m(arc BD) - m(arc AC))
36° = 1/2 * (5x - 2x)
36° = 1/2 * (3x)
72° = 3x
x = 72° / 3
x = 24°
- Calculate the measures of the arcs:
- Measure of arc AC = 2x = 2 * 24° = 48°.
- Measure of arc BD = 5x = 5 * 24° = 120°.
- Using the intersecting chords angle formula:
- Now we need to find ∠BED. The chords AD and BC intersect at E.
- According to the formula for the angle formed by two intersecting chords:
∠BED = 1/2 * (m(arc BD) + m(arc AC))
∠BED = 1/2 * (120° + 48°)
∠BED = 1/2 * (168°)
∠BED = 84°
Final Answer:
Ответ: 84