In the bottom diagram, we have points A, N, B, M on a circle. We are given that AB-diameter and LNBA = 73 degrees. We need to find LNMB.
If AB is a diameter, then the angle subtended by the diameter at any point on the circumference is 90 degrees. So, angle ANB = 90 degrees and angle AMB = 90 degrees.
We are given LNBA = 73 degrees. This is an inscribed angle subtending arc NA.
Therefore, the measure of arc NA = 2 * LNBA = 2 * 73 degrees = 146 degrees.
The central angle subtending arc NA is angle NOA. So, angle NOA = 146 degrees.
Since angle ANB = 90 degrees, we have angle AND + angle DNB = 90 degrees. (Assuming D is some point on AB or circumference).
In right triangle ANB, angle NAB + angle NBA = 90 degrees.
angle NAB + 73 degrees = 90 degrees.
angle NAB = 90 - 73 = 17 degrees.
Angle NAB subtends arc NB. So, arc NB = 2 * angle NAB = 2 * 17 degrees = 34 degrees.
The central angle subtending arc NB is angle NOB. So, angle NOB = 34 degrees.
We need to find LNMB. This is an inscribed angle subtending arc NB.
Therefore, LNMB = (1/2) * arc NB.
LNMB = (1/2) * 34 degrees = 17 degrees.
Let's verify using angles in triangle ANB.
Angle ANB = 90 degrees (subtended by diameter AB).
Angle NBA = 73 degrees (given).
Angle BAN = 180 - 90 - 73 = 17 degrees.
The angle LNMB is an inscribed angle subtending arc NB. The inscribed angle subtending the same arc NB is angle NAB.
Therefore, LNMB = angle NAB = 17 degrees.
Ответ: 17°