г.
3\frac{5}{6}+(-\frac{14}{15}) = 3\frac{25}{30} - \frac{28}{30} = 2\frac{55}{30} - \frac{28}{30} = 2\frac{27}{30} = 2\frac{9}{10}
2\frac{6}{7}+(-\frac{4}{7}) = 2\frac{6}{7} - \frac{4}{7} = 2\frac{2}{7}
-5\frac{2}{9}+3\frac{2}{9} = -2
-1\frac{2}{3}+4\frac{1}{3} = 2\frac{2}{3}
3+(-\frac{2}{4}) = 3 - \frac{1}{2} = 2\frac{1}{2}
-5+1\frac{3}{8} = -3\frac{5}{8}
2+(-7) = -5
4\frac{5}{6}+(-9) = 4\frac{5}{6} - 9 = -4\frac{1}{6}
-2\frac{13}{6}+6\frac{1}{13} = -4\frac{1}{6} + 6\frac{1}{13} = -4\frac{13}{78} + 6\frac{6}{78} = 1\frac{71}{78}
1\frac{7}{12}+(-5) = 1\frac{7}{12} - 5 = -3\frac{5}{12}
Задание 96. Приведите дроби к общему знаменателю и выполните действие.
А.
\frac{1}{2}+\frac{2}{3}+(\frac{3}{6}+\frac{4}{6})+\frac{1}{6} = \frac{3}{6} + \frac{4}{6} + \frac{7}{6} + \frac{1}{6} = \frac{15}{6} = 2\frac{3}{6} = 2\frac{1}{2}
\frac{3}{5}+(\frac{1}{-2}) = \frac{3}{5} - \frac{1}{2} = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}
\frac{5}{7}+\frac{1}{3} = \frac{15}{21} + \frac{7}{21} = \frac{22}{21} = 1\frac{1}{21}
\frac{2}{3}+(-\frac{4}{5}) = \frac{2}{3} - \frac{4}{5} = \frac{10}{15} - \frac{12}{15} = -\frac{2}{15}
\frac{5}{9}+(\frac{1}{-2}) = \frac{5}{9} - \frac{1}{2} = \frac{10}{18} - \frac{9}{18} = \frac{1}{18}
\frac{3}{7}+(\frac{2}{-5}) = \frac{3}{7} - \frac{2}{5} = \frac{15}{35} - \frac{14}{35} = \frac{1}{35}
\frac{7}{9}+(\frac{1}{-4}) = \frac{7}{9} - \frac{1}{4} = \frac{28}{36} - \frac{9}{36} = \frac{19}{36}
\frac{5}{6}+\frac{4}{5} = \frac{25}{30} + \frac{24}{30} = \frac{49}{30} = 1\frac{19}{30}
\frac{9}{11}+\frac{1}{3} = \frac{27}{33} + \frac{11}{33} = \frac{38}{33} = 1\frac{5}{33}
\frac{5}{8}+(\frac{-2}{3}) = \frac{5}{8} - \frac{2}{3} = \frac{15}{24} - \frac{16}{24} = -\frac{1}{24}
1\frac{3}{4}+(-\frac{1}{3}) = 1\frac{3}{4} - \frac{1}{3} = 1\frac{9}{12} - \frac{4}{12} = 1\frac{5}{12}
-2\frac{6}{11}+1\frac{1}{2} = -2\frac{12}{22} + 1\frac{11}{22} = -1\frac{1}{22}
-\frac{2}{3}+1\frac{7}{10} = -\frac{20}{30} + 1\frac{21}{30} = \frac{1}{30}
4\frac{7}{13}+(-\frac{1}{2}) = 4\frac{7}{13} - \frac{1}{2} = 4\frac{14}{26} - \frac{13}{26} = 4\frac{1}{26}
1\frac{1}{7}+(-\frac{2}{3}) = 1\frac{1}{7} - \frac{2}{3} = 1\frac{3}{21} - \frac{14}{21} = \frac{24}{21} - \frac{14}{21} = \frac{10}{21}
1\frac{3}{5}+(\frac{-2}{3}) = 1\frac{3}{5} - \frac{2}{3} = 1\frac{9}{15} - \frac{10}{15} = \frac{24}{15} - \frac{10}{15} = \frac{14}{15}
-4\frac{1}{6}+2\frac{7}{7} = -4\frac{1}{6} + 3 = -1\frac{1}{6}
4\frac{2}{5}+(-\frac{3}{4}) = 4\frac{2}{5} - \frac{3}{4} = 4\frac{8}{20} - \frac{15}{20} = 3\frac{28}{20} - \frac{15}{20} = 3\frac{13}{20}
3\frac{2}{9}+(-\frac{5}{2}) = 3\frac{2}{9} - \frac{5}{2} = 3\frac{4}{18} - \frac{45}{18} = 2\frac{22}{18} - \frac{45}{18} = -2\frac{23}{18} = -2\frac{5}{18}
-2\frac{1}{11}+3\frac{1}{5} = -2\frac{5}{55} + 3\frac{11}{55} = \frac{6}{55}
Ответ: См. решение выше