1.12 г) $$2\frac{1}{3} \cdot \frac{6}{7} - (1\frac{11}{12} - \frac{1}{3}) : 4\frac{3}{4}$$

$$\begin{aligned} &2\frac{1}{3} \cdot \frac{6}{7} - (1\frac{11}{12} - \frac{1}{3}) : 4\frac{3}{4} = \\ &= \frac{7}{3} \cdot \frac{6}{7} - (\frac{23}{12} - \frac{4}{12}) : \frac{19}{4} = \\ &= 2 - \frac{19}{12} : \frac{19}{4} = \\ &= 2 - \frac{19}{12} \cdot \frac{4}{19} = \\ &= 2 - \frac{1}{3} = \\ &= \frac{6}{3} - \frac{1}{3} = \\ &= \frac{5}{3} = \\ &= 1\frac{2}{3} \end{aligned}$$ Ответ: $$1\frac{2}{3}$$