We are given two parallel lines \( a \) and \( b \), and a transversal line.
Angle 1 and the angle adjacent to Angle 3 on line \( a \) are consecutive interior angles. Consecutive interior angles are supplementary, meaning they add up to 180 degrees.
Let the angle adjacent to Angle 3 on line \( a \) be \( \alpha \).
\( \angle 1 + \alpha = 180^{\circ} \)
\( 128^{\circ} + \alpha = 180^{\circ} \)
\( \alpha = 180^{\circ} - 128^{\circ} \)
\( \alpha = 52^{\circ} \)
Angle 3 and \( \alpha \) are alternate interior angles. Alternate interior angles are equal when lines are parallel.
\( \angle 3 = \alpha \)
\( \angle 3 = 52^{\circ} \)
Note: Angle 2 is not needed to solve for Angle 3 in this configuration.
Answer: \( \angle 3 = 52^{\circ} \)