Let's break down these geometry problems step by step!
We have a right-angled triangle ABC, where:
The sum of angles in any triangle is always 180 degrees.
So, Angle BAC + Angle ABC + Angle C = 180 degrees
\[ 70^\circ + \text{Angle ABC} + 90^\circ = 180^\circ \]
\[ \text{Angle ABC} = 180^\circ - 90^\circ - 70^\circ \]
\[ \text{Angle ABC} = 20^\circ \]
In the second triangle, we have:
The exterior angle and the interior angle at a vertex are supplementary, meaning they add up to 180 degrees.
So, Interior Angle ABC + Exterior Angle at B = 180 degrees
\[ \text{Interior Angle ABC} + 124^\circ = 180^\circ \]
\[ \text{Interior Angle ABC} = 180^\circ - 124^\circ \]
\[ \text{Interior Angle ABC} = 56^\circ \]
Now, we can find Angle BAC using the sum of angles in a triangle:
Angle BAC + Angle ABC + Angle C = 180 degrees
\[ \text{Angle BAC} + 56^\circ + 90^\circ = 180^\circ \]
\[ \text{Angle BAC} = 180^\circ - 90^\circ - 56^\circ \]
\[ \text{Angle BAC} = 34^\circ \]
Ответ: В первом треугольнике угол B равен 20 градусам. Во втором треугольнике угол A равен 34 градусам.