Ответ:
Используем формулы приведения:
\(\sin(180^\circ-\alpha)=\sin\alpha\), \(\cos(180^\circ-\alpha)=-\cos\alpha\).
| α | 30° | 45° | 60° | 120° | 135° | 150° |
|---|---|---|---|---|---|---|
| sin α | \(\frac{1}{2}\) | \(\frac{\sqrt{2}}{2}\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{\sqrt{2}}{2}\) | \(\frac{1}{2}\) |
| cos α | \(\frac{\sqrt{3}}{2}\) | \(\frac{\sqrt{2}}{2}\) | \(\frac{1}{2}\) | \(-\frac{1}{2}\) | \(-\frac{\sqrt{2}}{2}\) | \(-\frac{\sqrt{3}}{2}\) |
Ответ: \(\sin120^\circ=\frac{\sqrt3}{2}\), \(\sin135^\circ=\frac{\sqrt2}{2}\), \(\sin150^\circ=\frac12\); \(\cos120^\circ=-\frac12\), \(\cos135^\circ=-\frac{\sqrt2}{2}\), \(\cos150^\circ=-\frac{\sqrt3}{2}\).
