Ответ:

Используем формулы приведения:

\(\sin(180^\circ-\alpha)=\sin\alpha\), \(\cos(180^\circ-\alpha)=-\cos\alpha\).

α30°45°60°120°135°150°
sin α\(\frac{1}{2}\)\(\frac{\sqrt{2}}{2}\)\(\frac{\sqrt{3}}{2}\)\(\frac{\sqrt{3}}{2}\)\(\frac{\sqrt{2}}{2}\)\(\frac{1}{2}\)
cos α\(\frac{\sqrt{3}}{2}\)\(\frac{\sqrt{2}}{2}\)\(\frac{1}{2}\)\(-\frac{1}{2}\)\(-\frac{\sqrt{2}}{2}\)\(-\frac{\sqrt{3}}{2}\)

Ответ: \(\sin120^\circ=\frac{\sqrt3}{2}\), \(\sin135^\circ=\frac{\sqrt2}{2}\), \(\sin150^\circ=\frac12\); \(\cos120^\circ=-\frac12\), \(\cos135^\circ=-\frac{\sqrt2}{2}\), \(\cos150^\circ=-\frac{\sqrt3}{2}\).