\[\frac{a^4}{b^4} = \left(\frac{a}{b}\right)^4 = (-2)^4 = 16\]
\[\frac{a^5}{2b^5} = \frac{(-2b)^5}{2b^5} = \frac{(-2)^5 \cdot b^5}{2b^5} = \frac{-32b^5}{2b^5} = -16\]
\[\frac{2b^3}{a^3} = \frac{2b^3}{(-2b)^3} = \frac{2b^3}{(-2)^3 \cdot b^3} = \frac{2b^3}{-8b^3} = -\frac{1}{4}\]
Ответ: a) 16; б) -16; в) -1/4