К) $$9\frac{11}{16}-3\frac{7}{24} = \frac{9 \cdot 16 + 11}{16} - \frac{3 \cdot 24 + 7}{24} = \frac{144+11}{16} - \frac{72+7}{24} = \frac{155}{16} - \frac{79}{24} = \frac{155 \cdot 3}{16 \cdot 3} - \frac{79 \cdot 2}{24 \cdot 2} = \frac{465}{48} - \frac{158}{48} = \frac{465-158}{48} = \frac{307}{48} = 6\frac{19}{48}$$