к) -\frac{4}{7} + \frac{7}{2}; л) \frac{8}{5} + (-\frac{12}{7}); н) -2 + 1\frac{1}{3}; о) 3 + (-1\frac{7}{12}); п) 2\frac{2}{3} + (-1\frac{6}{5}); p) -5\frac{1}{3} + 4,5.

Ответ: к) 4 \frac{13}{14}; л) -\frac{20}{35}; н) -\frac{2}{3}; о) 1 \frac{5}{12}; п) -\frac{13}{15}; p) -\frac{5}{6}

Решаем по порядку:

1. к) -\[\frac{4}{7}\] + \frac{7}{2} = -\frac{4\cdot2}{7\cdot2} + \frac{7\cdot7}{2\cdot7} = -\frac{8}{14} + \frac{49}{14} = \frac{49-8}{14} = \frac{41}{14} = 4 \frac{13}{14}
2. л) \frac{8}{5} + (-\frac{12}{7}) = \frac{8}{5} - \frac{12}{7} = \frac{8\cdot7}{5\cdot7} - \frac{12\cdot5}{7\cdot5} = \frac{56}{35} - \frac{60}{35} = \frac{56-60}{35} = -\frac{4}{35}
3. н) -2 + 1\frac{1}{3} = -2 + \frac{4}{3} = -\frac{6}{3} + \frac{4}{3} = \frac{-6+4}{3} = -\frac{2}{3} = -\frac{2}{3}
4. о) 3 + (-1\frac{7}{12}) = 3 - 1\frac{7}{12} = \frac{36}{12} - \frac{19}{12} = \frac{36-19}{12} = \frac{17}{12} = 1 \frac{5}{12}
5. п) 2\frac{2}{3} + (-1\frac{6}{5}) = \frac{8}{3} - \frac{11}{5} = \frac{8\cdot5}{3\cdot5} - \frac{11\cdot3}{5\cdot3} = \frac{40}{15} - \frac{33}{15} = \frac{40-33}{15} = \frac{7}{15} = \frac{7}{15}
6. p) -5\frac{1}{3} + 4,5 = -\frac{16}{3} + \frac{9}{2} = -\frac{16\cdot2}{3\cdot2} + \frac{9\cdot3}{2\cdot3} = -\frac{32}{6} + \frac{27}{6} = \frac{-32+27}{6} = -\frac{5}{6} = -\frac{5}{6}

Ответ: к) 4 \frac{13}{14}; л) -\frac{20}{35}; н) -\frac{2}{3}; о) 1 \frac{5}{12}; п) -\frac{13}{15}; p) -\frac{5}{6}