Карточка 2: 1) 12b/(18b³) =; 2) 15p⁴q/(25p²q³) =; 3) (y²−25)/(y+5) =; 4) (4d+12)/(8d+24) =; 5) (k²−6k)/(k²−36) =; 6) (2t−10)/(t²−5t) =.

1. \(\dfrac{12b}{18b^3}=\dfrac{2}{3b^2}\).
2. \(\dfrac{15p^4q}{25p^2q^3}=\dfrac{3p^2}{5q^2}\).
3. \(\dfrac{y^2-25}{y+5}=\dfrac{(y-5)(y+5)}{y+5}=y-5\).
4. \(\dfrac{4d+12}{8d+24}=\dfrac{4(d+3)}{8(d+3)}=\dfrac12\).
5. \(\dfrac{k^2-6k}{k^2-36}=\dfrac{k(k-6)}{(k-6)(k+6)}=\dfrac{k}{k+6}\).
6. \(\dfrac{2t-10}{t^2-5t}=\dfrac{2(t-5)}{t(t-5)}=\dfrac2t\).

Ответ: 1) \(\frac2{3b^2}\); 2) \(\frac{3p^2}{5q^2}\); 3) \(y-5\); 4) \(\frac12\); 5) \(\frac{k}{k+6}\); 6) \(\frac2t\).