11\(\frac{2}{5}\) + 7\(\frac{1}{2}\) (285\(\frac{3}{5}\) + 14 - 1\(\frac{23}{30}\) + \(\frac{13}{50}\)) ÷ (24\(\frac{2}{5}\) - 10\(\frac{31}{100}\)) =
4\(\frac{1}{5}\) ÷ 1\(\frac{1}{5}\) = 2\(\frac{3}{4}\) × 4 - 1\(\frac{7}{18}\)x
\(\frac{1}{4}\) × 4\(\frac{3}{4}\) × \(\frac{16}{57}\) + (4\(\frac{2}{3}\) + 1\(\frac{1}{2}\))x + \(\frac{5}{27}\) × 4\(\frac{1}{2}\) =
3\(\frac{1}{8}\) ÷ (x - 4\(\frac{7}{24}\)) = \(\frac{17}{18}\) + 1\(\frac{5}{6}\)