a) 5,2 + (1,1 - 3,8) = 5,2 + (-2,7) = 5,2 - 2,7 = 2,5
б) -(2,77 - 7 4\(\frac{7}{9}\)) - (0,23 - 44 7\(\frac{4}{9}\)) = -(277 7\(\frac{277}{100} - \frac{7}{9}\)) - (23 4\(\frac{23}{100} - \frac{4}{9}\)) = -(\(\frac{277 \cdot 9 - 7 \cdot 100}{900}\)) - (\(\frac{23 \cdot 9 - 4 \cdot 100}{900}\)) = -(\(\frac{2493 - 700}{900}\)) - (\(\frac{207 - 400}{900}\)) = -\(\frac{1793}{900}\) - (\(\frac{-193}{900}\)) = -\(\frac{1793}{900}\) + \(\frac{193}{900}\) = \(\frac{-1793 + 193}{900}\) = \(\frac{-1600}{900}\) = -\(\frac{16}{9}\) = -1 7\(\frac{1 7}{9}\)
a + (a - b) - (2a - b) + 2b = a + a - b - 2a + b + 2b = (a + a - 2a) + (-b + b + 2b) = 2b
a) 6x ⋅ (-2) = -12
б) (-2,4) ⋅ (-x) ⋅ (-5) = -2,4 ⋅ 5 ⋅ x = -12
a) 2m + 3m - 6m = (2 + 3 - 6)m = -m
б) m - 1 2\(\frac{1}{2}\)m - 0,3m + 2m = (1 - 1 2\(\frac{1}{2}\) - 0,3 + 2)m = (1 - 0,5 - 0,3 + 2)m = (3 - 0,8)m = 2,2m
6m - (2m + 3 5\(\frac{3}{5}\)) + (4m - 11 20\(\frac{11}{20}\)) = 6m - 2m - 3 5\(\frac{3}{5}\) + 4m - 11 20\(\frac{11}{20}\) = (6 - 2 + 4)m - 3 5\(\frac{3}{5}\) - 11 20\(\frac{11}{20}\) = 8m - 12 11\(\frac{12}{20}\) - 11 20\(\frac{11}{20}\) = 8m - 23 20\(\frac{23}{20}\) = 8m - 1 3\(\frac{1 3}{20}\)
* 5 7\(\frac{5}{7}\) (2,8c - 41 5\(\frac{1}{5}\)d) - 2,4 (5 6\(\frac{5}{6}\)c - 1,5d) = (\(\frac{5}{7}\) ⋅ 2,8c - \(\frac{5}{7}\) ⋅ \(\frac{21}{5}\)d) - (2,4 ⋅ \(\frac{5}{6}\)c - 2,4 ⋅ 1,5d) = (2c - 3d) - (2c - 3,6d) = 2c - 3d - 2c + 3,6d = (2c - 2c) + (-3d + 3,6d) = 0,6d
Ответ: Решения выше