льная работа a12x1925 26(m+n) -a40x3126 6bc(m+n) 44c3d³ (c-d) 3c³-3cd² = 100cd* (d-c) 6dc2-603 8-3c 9c2-64 (x - y)² 2 = X لاج - ج -

$$ \frac{a^{12}x^{19}z^5}{-a^{40}x^{31}z^6} = \frac{a^{12-40}x^{19-31}z^{5-6}}{-1} = -a^{-28}x^{-12}z^{-1} = -\frac{1}{a^{28}x^{12}z} $$

Ответ: $$\frac{-1}{a^{28}x^{12}z}$$

$$ \frac{2b(m+n)}{6bc(m+n)} = \frac{2b}{6bc} = \frac{1}{3c} $$

Ответ: $$\frac{1}{3c}$$

$$ \frac{44c^3d^8(c-d)}{100c^5d^4(d-c)} = -\frac{44c^3d^8(d-c)}{100c^5d^4(d-c)} = -\frac{44d^4}{100c^2} = -\frac{11d^4}{25c^2} $$

Ответ: $$\frac{-11d^4}{25c^2}$$

$$ \frac{3c^3-3cd^2}{6dc^2-6d^3} = \frac{3c(c^2-d^2)}{6d(c^2-d^2)} = \frac{3c}{6d} = \frac{c}{2d} $$

Ответ: $$\frac{c}{2d}$$

$$ \frac{8-3c}{9c^2-64} = \frac{-(3c-8)}{(3c-8)(3c+8)} = \frac{-1}{3c+8} $$

Ответ: $$\frac{-1}{3c+8}$$

$$ \frac{(x-y)^2}{x^2-y^2} = \frac{(x-y)(x-y)}{(x-y)(x+y)} = \frac{x-y}{x+y} $$

Ответ: $$\frac{x-y}{x+y}$$