36. (-1/2 m²n³)³.

$$\left(-\frac{1}{2} m^2n^3\right)^3 = \left(-\frac{1}{2}\right)^3 \cdot (m^2)^3 \cdot (n^3)^3 = -\frac{1^3}{2^3} \cdot m^{2\cdot 3} \cdot n^{3\cdot 3} = -\frac{1}{8} m^6n^9$$

Ответ: -1/8 m⁶n⁹