м) \(3\frac{2}{5}z + \frac{2}{3} - 3 = \frac{4}{5}.\)
- \(3\frac{2}{5}z = \frac{17}{5}z\)
- \(\frac{17}{5}z = \frac{4}{5} - \frac{2}{3} + 3\)
- \(\frac{17}{5}z = \frac{4 \cdot 3}{5 \cdot 3} - \frac{2 \cdot 5}{3 \cdot 5} + \frac{3 \cdot 15}{15}\)
- \(\frac{17}{5}z = \frac{12}{15} - \frac{10}{15} + \frac{45}{15}\)
- \(\frac{17}{5}z = \frac{47}{15}\)
- \(z = \frac{47}{15} : \frac{17}{5}\)
- \(z = \frac{47}{15} \cdot \frac{5}{17}\)
- \(z = \frac{47 \cdot 5}{15 \cdot 17}\)
- \(z = \frac{47}{3 \cdot 17}\)
- \(z = \frac{47}{51}\)
Ответ: 47/51