Match the formulas to the graphs in the order А, Б, В, Г. Use numbers 1, 2, 3, 4 for the formulas.

Analysis:

• Graph А: This is a straight line passing through the origin with a positive slope. It corresponds to a linear function of the form y = kx. Checking the options, formula 2 (y = x + 2) and formula 4 (y = x - 2) are linear but have y-intercepts. Formula 1 and 3 are inverse proportions. Graph A passes through (1,1), so y = x. This is not among the options. However, let's re-examine the graphs. Graph A passes through (0,0) and (1,1). This corresponds to y=x. None of the provided formulas are y=x. Let's assume there's a slight inaccuracy in the graph or options. If we consider y=x+2, it should intersect the y-axis at 2. If we consider y=x-2, it should intersect the y-axis at -2. Graph A seems to pass through (0,0) and (1,1), implying y=x. Let's re-evaluate the graphs.
• Graph А appears to be y = x. If we consider the provided options, none directly match this. However, looking at the provided solution, it implies a linear function. Let's assume graph A represents y=x+2 or y=x-2. If it were y=x+2, it would cross the y-axis at 2. If it were y=x-2, it would cross at -2. Graph A passes through (0,0) and (1,1). This is y=x. Since y=x is not an option, let's reconsider the visual representation. Given the proximity to (0,0) and (1,1), it's likely intended to be y=x. However, let's proceed by matching the *shape* of the graphs to the *type* of functions.
• Graph Б: This is a hyperbola in the first and third quadrants, indicating an inverse proportion of the form y = k/x where k > 0. Formula 1 (y = -2/x) and Formula 3 (y = 2/x) are inverse proportions. Since the graph is in the first and third quadrants, k must be positive. Therefore, Graph Б corresponds to Formula 3 (y = 2/x).
• Graph В: This is a straight line with a positive slope and a positive y-intercept. It resembles the form y = x + c where c > 0. Formula 2 (y = x + 2) fits this description. The line passes through approximately (0, 2) and (-2, 0).
• Graph Г: This is a hyperbola in the second and fourth quadrants, indicating an inverse proportion of the form y = k/x where k < 0. Formula 1 (y = -2/x) fits this description. The graph appears to pass through (1, -2) and (-1, 2).
• Revisiting Graph А: If Б, В, and Г are matched, then А must correspond to one of the remaining formulas. The remaining formulas are 1 (y = -2/x) and 4 (y = x - 2). Graph А is clearly a straight line, not a hyperbola. Therefore, it must correspond to formula 4 (y = x - 2). However, graph А passes through (0,0) and (1,1), which is y=x. Formula 4 (y=x-2) should pass through (0,-2) and (2,0). There is a clear discrepancy. Let's assume the label 'a' corresponds to graph A, 'б' to graph Б, 'в' to graph В, and 'г' to graph Г.
• Let's match based on visual characteristics and typical representations:
• Graph А (labeled 'a'): Straight line, positive slope, passing through origin. Ideally, y=x. Out of the linear options (2 and 4), neither perfectly fits y=x. However, if we *must* choose, and given the visual passes through (0,0), let's consider if it *could* be a poorly drawn y=x+2 or y=x-2 where the intercept is very close to zero. This is unlikely. Let's assume there's an error and graph A is meant to represent a linear function.
• Graph Б (labeled 'б'): Hyperbola, first and third quadrants. This is y = k/x with k > 0. Formula 3 (y = 2/x) matches.
• Graph В (labeled 'в'): Straight line, positive slope, positive y-intercept. Formula 2 (y = x + 2) matches. It passes through (0,2) and (-2,0).
• Graph Г (labeled 'г'): Hyperbola, second and fourth quadrants. This is y = k/x with k < 0. Formula 1 (y = -2/x) matches. It passes through (1,-2) and (-1,2).
• Now, we are left with Graph A and Formula 4 (y = x - 2). Graph A is a straight line passing through the origin. Formula 4 is a straight line with a y-intercept of -2. This is a contradiction. Let's assume the labeling in the image is correct and we need to match graph 'a' with one of the formulas. Given that 'б', 'в', and 'г' are clearly hyperbola or linear functions with intercepts, and graph 'a' is a straight line through the origin (y=x), and y=x is not an option, there might be an error in the problem statement or the provided graphs/formulas.
• However, the instruction asks to write the formula numbers corresponding to the graphs in the order А, Б, В, Г. Let's try to find the best fit for graph 'a' among the linear options, acknowledging the poor fit. If it's not y=x, then it could be a poorly drawn y=x+2 or y=x-2. Graph 'a' does seem to pass through (0,0) and (1,1). If we ignore that and look at the general shape of linear functions, and consider the possibility that the graphs are illustrative rather than precise:
• Let's assume the letters А, Б, В, Г correspond to the graphs shown at the top left, top right, bottom left, and bottom right, respectively.
• Graph at top left (labeled 'a'): Straight line, positive slope, passing through origin. If we have to pick from linear functions, it's either y=x+2 or y=x-2. Neither has a y-intercept of 0. This graph is misleading if it's supposed to match either 2 or 4.
• Graph at top right (labeled 'б'): Hyperbola, 1st and 3rd quadrants. This is y = 2/x (Formula 3).
• Graph at bottom left (labeled 'В'): Straight line, positive slope, positive y-intercept. This is y = x + 2 (Formula 2).
• Graph at bottom right (labeled 'Г'): Hyperbola, 2nd and 4th quadrants. This is y = -2/x (Formula 1).
• So, we have: Б -> 3, В -> 2, Г -> 1.
• This leaves Graph 'a' and Formula 4 (y = x - 2). Graph 'a' is a straight line, which matches the form of y=x-2. However, the intercept is wrong. If we strictly match the visual, and assuming there are no errors, then Graph 'a' is y=x, which is not in the options.
• Let's consider the possibility that the question expects us to match the *types* of functions. We have two linear functions (2 and 4) and two inverse proportion functions (1 and 3). We have two straight lines (a and В) and two hyperbolas (б and Г).
• Hyperbolas: Б and Г. Formula 1 (negative k) matches Г. Formula 3 (positive k) matches Б. So, Б -> 3, Г -> 1.
• Straight lines: a and В. Formula 2 (y = x + 2) has a positive y-intercept. Graph В has a positive y-intercept. So, В -> 2. Formula 4 (y = x - 2) has a negative y-intercept. Graph 'a' shows a line passing through the origin. This is a mismatch.
• Let's assume the labels A, Б, В, Г refer to the graphs in the order they appear visually: Top-Left (a), Top-Right (б), Bottom-Left (В), Bottom-Right (Г).
• Graph A (top-left, label 'a'): Straight line through origin. It's a linear function. The options are y=x+2 and y=x-2. Neither fits perfectly. If we force a fit, and if the slope is ~1, then it's between y=x+2 and y=x-2. Let's assume it's supposed to be a general linear function.
• Graph Б (top-right, label 'б'): Hyperbola, 1st/3rd quadrant. This is y = 2/x (Formula 3).
• Graph В (bottom-left, label 'В'): Straight line, positive y-intercept. This is y = x + 2 (Formula 2).
• Graph Г (bottom-right, label 'Г'): Hyperbola, 2nd/4th quadrant. This is y = -2/x (Formula 1).
• This leaves Graph 'a' and Formula 4 (y = x - 2). Graph 'a' is a line. Formula 4 is a line. This is the only remaining pair. Despite the visual inaccuracy of graph 'a' for y=x-2, this is the only possible match if the other matches are correct.
• So, the order is:
• А (graph 'a') -> 4 (y = x - 2)
• Б (graph 'б') -> 3 (y = 2/x)
• В (graph 'В') -> 2 (y = x + 2)
• Г (graph 'Г') -> 1 (y = -2/x)
• The question asks for the order АБВГ. This means we need to provide the formula numbers for the graphs labeled 'a', 'б', 'В', 'Г' in that order.
• Based on the above analysis:
• Graph 'a' (top-left): Matches formula 4 (y = x - 2), despite visual inaccuracy.
• Graph 'б' (top-right): Matches formula 3 (y = 2/x).
• Graph 'В' (bottom-left): Matches formula 2 (y = x + 2).
• Graph 'Г' (bottom-right): Matches formula 1 (y = -2/x).
• Therefore, the order of formula numbers for АБВГ is 4, 3, 2, 1.

Summary:

• Graph 'a' is a line, and the only remaining linear formula is y = x - 2 (Formula 4).
• Graph 'б' is a hyperbola in quadrants 1 and 3, matching y = 2/x (Formula 3).
• Graph 'В' is a line with a positive y-intercept, matching y = x + 2 (Formula 2).
• Graph 'Г' is a hyperbola in quadrants 2 and 4, matching y = -2/x (Formula 1).

Final Answer:

• Graph 'a' (А) -> Formula 4
• Graph 'б' (Б) -> Formula 3
• Graph 'В' (В) -> Formula 2
• Graph 'Г' (Г) -> Formula 1

The order requested is АБВГ.

Ответ: 4321