\[ \frac{2}{\sqrt{3}-1} \cdot \frac{\sqrt{3}+1}{\sqrt{3}+1} = \frac{2(\sqrt{3}+1)}{(\sqrt{3})^2 - 1^2} = \frac{2(\sqrt{3}+1)}{3-1} = \frac{2(\sqrt{3}+1)}{2} = \sqrt{3}+1 \]
\[ (\sqrt{3}+1) - \sqrt{3} \]
\[ \sqrt{3}+1 - \sqrt{3} = 1 \]
Ответ: 1