Контрольные задания > N
ρ = ρ(φ)
1
p = 6 cos(p)
2
p = -2sin()
3
p = 2 cos(p)
4
p = -4 sin()
5 p = -4 cos(p)
6
p = -2cos(p)
7
ρ
p = 4 cos(φ)
8
p = -6 sin()
9
p = 4 sin()
10 p = 2sin()
Вопрос:
N
ρ = ρ(φ)
1
p = 6 cos(p)
2
p = -2sin()
3
p = 2 cos(p)
4
p = -4 sin()
5 p = -4 cos(p)
6
p = -2cos(p)
7
ρ
p = 4 cos(φ)
8
p = -6 sin()
9
p = 4 sin()
10 p = 2sin()