Вопрос:

на «3» 1) 15$$\frac{17}{26}$$ + 22$$\frac{3}{26}$$= 2) 209$$\frac{1}{29}$$+ 105= 3) 136$$\frac{15}{31}$$ + 107$$\frac{7}{31}$$= 4) 64$$\frac{6}{10}$$+ 12$$\frac{9}{10}$$= 5) 26$$\frac{19}{25}$$+ 35$$\frac{1}{25}$$= 6) 19$$\frac{6}{17}$$+ 29 = 7) 7$$\frac{7}{8}$$+ 59$$\frac{7}{8}$$ = 8) 203$$\frac{19}{41}$$ - 40$$\frac{6}{41}$$= 9) 141$$\frac{11}{40}$$ - 41$$\frac{21}{40}$$= 10) 419$$\frac{8}{23}$$ - 105 = 11) 25 - 24$$\frac{18}{23}$$= 12) 55$$\frac{113}{144}$$ - 8= 13) 8$$\frac{2}{74}$$ - 1$$\frac{7}{74}$$= 14) 6$$\frac{3}{11}$$ - 2= 15) 85$$\frac{2}{4}$$ - 71$$\frac{3}{4}$$= на «4» 16) 35$$\frac{10}{13}$$ - 25$$\frac{12}{13}$$= 17) 506$$\frac{9}{13}$$ - 72 = 18) 29 - 18$$\frac{27}{30}$$= 19) 19$$\frac{13}{149}$$ - 16 = 20) 4$$\frac{4}{15}$$ - 1$$\frac{9}{15}$$= 21) 8$$\frac{6}{23}$$ - 3= 22) 6 - 1$$\frac{5}{7}$$= 23) 1$$\frac{13}{15}$$ - 1$$\frac{2}{15}$$= 24) 28$$\frac{7}{20}$$ - 7= 25) 8$$\frac{2}{44}$$ - 1$$\frac{7}{44}$$= 26) 18$$\frac{2}{14}$$ - 13$$\frac{7}{14}$$= 27) 51 - 1$$\frac{7}{8}$$= 28) 5$$\frac{5}{4}$$ - 2$$\frac{1}{4}$$= 29) 36$$\frac{4}{20}$$ - 3= 30) 81$$\frac{2}{14}$$ - 63$$\frac{7}{14}$$= на «5» 1$$\frac{11}{12}$$ + 2$$\frac{10}{12}$$= 9$$\frac{2}{3}$$ + 11$$\frac{2}{3}$$= 6$$\frac{5}{6}$$ + 3$$\frac{4}{6}$$= 4$$\frac{7}{9}$$ + 7$$\frac{8}{9}$$= 8$$\frac{4}{10}$$ + 6$$\frac{9}{10}$$= 10$$\frac{32}{33}$$ + 11$$\frac{12}{33}$$= 12$$\frac{3}{16}$$ + 33$$\frac{15}{16}$$= 4$$\frac{19}{21}$$ + 9$$\frac{20}{21}$$= 15$$\frac{54}{55}$$ + 51$$\frac{41}{55}$$ =

Смотреть решения всех заданий с листа

Ответ:

Давай разберем по порядку каждый столбик примеров и решим их. Столбик «3» 1) \( 15\frac{17}{26} + 22\frac{3}{26} = (15 + 22) + (\frac{17}{26} + \frac{3}{26}) = 37 + \frac{20}{26} = 37 + \frac{10}{13} = 37\frac{10}{13} \) 2) \( 209\frac{1}{29} + 105 = (209 + 105) + \frac{1}{29} = 314 + \frac{1}{29} = 314\frac{1}{29} \) 3) \( 136\frac{15}{31} + 107\frac{7}{31} = (136 + 107) + (\frac{15}{31} + \frac{7}{31}) = 243 + \frac{22}{31} = 243\frac{22}{31} \) 4) \( 64\frac{6}{10} + 12\frac{9}{10} = (64 + 12) + (\frac{6}{10} + \frac{9}{10}) = 76 + \frac{15}{10} = 76 + 1\frac{5}{10} = 76 + 1\frac{1}{2} = 77\frac{1}{2} \) 5) \( 26\frac{19}{25} + 35\frac{1}{25} = (26 + 35) + (\frac{19}{25} + \frac{1}{25}) = 61 + \frac{20}{25} = 61 + \frac{4}{5} = 61\frac{4}{5} \) 6) \( 19\frac{6}{17} + 29 = (19 + 29) + \frac{6}{17} = 48 + \frac{6}{17} = 48\frac{6}{17} \) 7) \( 7\frac{7}{8} + 59\frac{7}{8} = (7 + 59) + (\frac{7}{8} + \frac{7}{8}) = 66 + \frac{14}{8} = 66 + 1\frac{6}{8} = 66 + 1\frac{3}{4} = 67\frac{3}{4} \) 8) \( 203\frac{19}{41} - 40\frac{6}{41} = (203 - 40) + (\frac{19}{41} - \frac{6}{41}) = 163 + \frac{13}{41} = 163\frac{13}{41} \) 9) \( 141\frac{11}{40} - 41\frac{21}{40} = (141 - 41) + (\frac{11}{40} - \frac{21}{40}) = 100 - \frac{10}{40} = 100 - \frac{1}{4} = 99\frac{3}{4} \) 10) \( 419\frac{8}{23} - 105 = (419 - 105) + \frac{8}{23} = 314 + \frac{8}{23} = 314\frac{8}{23} \) 11) \( 25 - 24\frac{18}{23} = (25 - 24) - \frac{18}{23} = 1 - \frac{18}{23} = \frac{23}{23} - \frac{18}{23} = \frac{5}{23} \) 12) \( 55\frac{113}{144} - 8 = (55 - 8) + \frac{113}{144} = 47 + \frac{113}{144} = 47\frac{113}{144} \) 13) \( 8\frac{2}{74} - 1\frac{7}{74} = (8 - 1) + (\frac{2}{74} - \frac{7}{74}) = 7 - \frac{5}{74} = 6\frac{69}{74} \) 14) \( 6\frac{3}{11} - 2 = (6 - 2) + \frac{3}{11} = 4 + \frac{3}{11} = 4\frac{3}{11} \) 15) \( 85\frac{2}{4} - 71\frac{3}{4} = (85 - 71) + (\frac{2}{4} - \frac{3}{4}) = 14 - \frac{1}{4} = 13\frac{3}{4} \) Столбик «4» 16) \( 35\frac{10}{13} - 25\frac{12}{13} = (35 - 25) + (\frac{10}{13} - \frac{12}{13}) = 10 - \frac{2}{13} = 9\frac{11}{13} \) 17) \( 506\frac{9}{13} - 72 = (506 - 72) + \frac{9}{13} = 434 + \frac{9}{13} = 434\frac{9}{13} \) 18) \( 29 - 18\frac{27}{30} = (29 - 18) - \frac{27}{30} = 11 - \frac{27}{30} = 10\frac{3}{30} = 10\frac{1}{10} \) 19) \( 19\frac{13}{149} - 16 = (19 - 16) + \frac{13}{149} = 3 + \frac{13}{149} = 3\frac{13}{149} \) 20) \( 4\frac{4}{15} - 1\frac{9}{15} = (4 - 1) + (\frac{4}{15} - \frac{9}{15}) = 3 - \frac{5}{15} = 3 - \frac{1}{3} = 2\frac{2}{3} \) 21) \( 8\frac{6}{23} - 3 = (8 - 3) + \frac{6}{23} = 5 + \frac{6}{23} = 5\frac{6}{23} \) 22) \( 6 - 1\frac{5}{7} = (6 - 1) - \frac{5}{7} = 5 - \frac{5}{7} = 4\frac{2}{7} \) 23) \( 1\frac{13}{15} - 1\frac{2}{15} = (1 - 1) + (\frac{13}{15} - \frac{2}{15}) = 0 + \frac{11}{15} = \frac{11}{15} \) 24) \( 28\frac{7}{20} - 7 = (28 - 7) + \frac{7}{20} = 21 + \frac{7}{20} = 21\frac{7}{20} \) 25) \( 8\frac{2}{44} - 1\frac{7}{44} = (8 - 1) + (\frac{2}{44} - \frac{7}{44}) = 7 - \frac{5}{44} = 6\frac{39}{44} \) 26) \( 18\frac{2}{14} - 13\frac{7}{14} = (18 - 13) + (\frac{2}{14} - \frac{7}{14}) = 5 - \frac{5}{14} = 4\frac{9}{14} \) 27) \( 51 - 1\frac{7}{8} = (51 - 1) - \frac{7}{8} = 50 - \frac{7}{8} = 49\frac{1}{8} \) 28) \( 5\frac{5}{4} - 2\frac{1}{4} = (5 - 2) + (\frac{5}{4} - \frac{1}{4}) = 3 + \frac{4}{4} = 3 + 1 = 4 \) 29) \( 36\frac{4}{20} - 3 = (36 - 3) + \frac{4}{20} = 33 + \frac{1}{5} = 33\frac{1}{5} \) 30) \( 81\frac{2}{14} - 63\frac{7}{14} = (81 - 63) + (\frac{2}{14} - \frac{7}{14}) = 18 - \frac{5}{14} = 17\frac{9}{14} \) Столбик «5» \( 1\frac{11}{12} + 2\frac{10}{12} = (1 + 2) + (\frac{11}{12} + \frac{10}{12}) = 3 + \frac{21}{12} = 3 + 1\frac{9}{12} = 4\frac{3}{4} \) \( 9\frac{2}{3} + 11\frac{2}{3} = (9 + 11) + (\frac{2}{3} + \frac{2}{3}) = 20 + \frac{4}{3} = 20 + 1\frac{1}{3} = 21\frac{1}{3} \) \( 6\frac{5}{6} + 3\frac{4}{6} = (6 + 3) + (\frac{5}{6} + \frac{4}{6}) = 9 + \frac{9}{6} = 9 + 1\frac{3}{6} = 10\frac{1}{2} \) \( 4\frac{7}{9} + 7\frac{8}{9} = (4 + 7) + (\frac{7}{9} + \frac{8}{9}) = 11 + \frac{15}{9} = 11 + 1\frac{6}{9} = 12\frac{2}{3} \) \( 8\frac{4}{10} + 6\frac{9}{10} = (8 + 6) + (\frac{4}{10} + \frac{9}{10}) = 14 + \frac{13}{10} = 14 + 1\frac{3}{10} = 15\frac{3}{10} \) \( 10\frac{32}{33} + 11\frac{12}{33} = (10 + 11) + (\frac{32}{33} + \frac{12}{33}) = 21 + \frac{44}{33} = 21 + 1\frac{11}{33} = 22\frac{1}{3} \) \( 12\frac{3}{16} + 33\frac{15}{16} = (12 + 33) + (\frac{3}{16} + \frac{15}{16}) = 45 + \frac{18}{16} = 45 + 1\frac{2}{16} = 46\frac{1}{8} \) \( 4\frac{19}{21} + 9\frac{20}{21} = (4 + 9) + (\frac{19}{21} + \frac{20}{21}) = 13 + \frac{39}{21} = 13 + 1\frac{18}{21} = 14\frac{6}{7} \) \( 15\frac{54}{55} + 51\frac{41}{55} = (15 + 51) + (\frac{54}{55} + \frac{41}{55}) = 66 + \frac{95}{55} = 66 + 1\frac{40}{55} = 67\frac{8}{11} \)

Ответ: Результаты вычислений выше.

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