Давай разберем по порядку каждый столбик примеров и решим их.
Столбик «3»
1) \( 15\frac{17}{26} + 22\frac{3}{26} = (15 + 22) + (\frac{17}{26} + \frac{3}{26}) = 37 + \frac{20}{26} = 37 + \frac{10}{13} = 37\frac{10}{13} \)
2) \( 209\frac{1}{29} + 105 = (209 + 105) + \frac{1}{29} = 314 + \frac{1}{29} = 314\frac{1}{29} \)
3) \( 136\frac{15}{31} + 107\frac{7}{31} = (136 + 107) + (\frac{15}{31} + \frac{7}{31}) = 243 + \frac{22}{31} = 243\frac{22}{31} \)
4) \( 64\frac{6}{10} + 12\frac{9}{10} = (64 + 12) + (\frac{6}{10} + \frac{9}{10}) = 76 + \frac{15}{10} = 76 + 1\frac{5}{10} = 76 + 1\frac{1}{2} = 77\frac{1}{2} \)
5) \( 26\frac{19}{25} + 35\frac{1}{25} = (26 + 35) + (\frac{19}{25} + \frac{1}{25}) = 61 + \frac{20}{25} = 61 + \frac{4}{5} = 61\frac{4}{5} \)
6) \( 19\frac{6}{17} + 29 = (19 + 29) + \frac{6}{17} = 48 + \frac{6}{17} = 48\frac{6}{17} \)
7) \( 7\frac{7}{8} + 59\frac{7}{8} = (7 + 59) + (\frac{7}{8} + \frac{7}{8}) = 66 + \frac{14}{8} = 66 + 1\frac{6}{8} = 66 + 1\frac{3}{4} = 67\frac{3}{4} \)
8) \( 203\frac{19}{41} - 40\frac{6}{41} = (203 - 40) + (\frac{19}{41} - \frac{6}{41}) = 163 + \frac{13}{41} = 163\frac{13}{41} \)
9) \( 141\frac{11}{40} - 41\frac{21}{40} = (141 - 41) + (\frac{11}{40} - \frac{21}{40}) = 100 - \frac{10}{40} = 100 - \frac{1}{4} = 99\frac{3}{4} \)
10) \( 419\frac{8}{23} - 105 = (419 - 105) + \frac{8}{23} = 314 + \frac{8}{23} = 314\frac{8}{23} \)
11) \( 25 - 24\frac{18}{23} = (25 - 24) - \frac{18}{23} = 1 - \frac{18}{23} = \frac{23}{23} - \frac{18}{23} = \frac{5}{23} \)
12) \( 55\frac{113}{144} - 8 = (55 - 8) + \frac{113}{144} = 47 + \frac{113}{144} = 47\frac{113}{144} \)
13) \( 8\frac{2}{74} - 1\frac{7}{74} = (8 - 1) + (\frac{2}{74} - \frac{7}{74}) = 7 - \frac{5}{74} = 6\frac{69}{74} \)
14) \( 6\frac{3}{11} - 2 = (6 - 2) + \frac{3}{11} = 4 + \frac{3}{11} = 4\frac{3}{11} \)
15) \( 85\frac{2}{4} - 71\frac{3}{4} = (85 - 71) + (\frac{2}{4} - \frac{3}{4}) = 14 - \frac{1}{4} = 13\frac{3}{4} \)
Столбик «4»
16) \( 35\frac{10}{13} - 25\frac{12}{13} = (35 - 25) + (\frac{10}{13} - \frac{12}{13}) = 10 - \frac{2}{13} = 9\frac{11}{13} \)
17) \( 506\frac{9}{13} - 72 = (506 - 72) + \frac{9}{13} = 434 + \frac{9}{13} = 434\frac{9}{13} \)
18) \( 29 - 18\frac{27}{30} = (29 - 18) - \frac{27}{30} = 11 - \frac{27}{30} = 10\frac{3}{30} = 10\frac{1}{10} \)
19) \( 19\frac{13}{149} - 16 = (19 - 16) + \frac{13}{149} = 3 + \frac{13}{149} = 3\frac{13}{149} \)
20) \( 4\frac{4}{15} - 1\frac{9}{15} = (4 - 1) + (\frac{4}{15} - \frac{9}{15}) = 3 - \frac{5}{15} = 3 - \frac{1}{3} = 2\frac{2}{3} \)
21) \( 8\frac{6}{23} - 3 = (8 - 3) + \frac{6}{23} = 5 + \frac{6}{23} = 5\frac{6}{23} \)
22) \( 6 - 1\frac{5}{7} = (6 - 1) - \frac{5}{7} = 5 - \frac{5}{7} = 4\frac{2}{7} \)
23) \( 1\frac{13}{15} - 1\frac{2}{15} = (1 - 1) + (\frac{13}{15} - \frac{2}{15}) = 0 + \frac{11}{15} = \frac{11}{15} \)
24) \( 28\frac{7}{20} - 7 = (28 - 7) + \frac{7}{20} = 21 + \frac{7}{20} = 21\frac{7}{20} \)
25) \( 8\frac{2}{44} - 1\frac{7}{44} = (8 - 1) + (\frac{2}{44} - \frac{7}{44}) = 7 - \frac{5}{44} = 6\frac{39}{44} \)
26) \( 18\frac{2}{14} - 13\frac{7}{14} = (18 - 13) + (\frac{2}{14} - \frac{7}{14}) = 5 - \frac{5}{14} = 4\frac{9}{14} \)
27) \( 51 - 1\frac{7}{8} = (51 - 1) - \frac{7}{8} = 50 - \frac{7}{8} = 49\frac{1}{8} \)
28) \( 5\frac{5}{4} - 2\frac{1}{4} = (5 - 2) + (\frac{5}{4} - \frac{1}{4}) = 3 + \frac{4}{4} = 3 + 1 = 4 \)
29) \( 36\frac{4}{20} - 3 = (36 - 3) + \frac{4}{20} = 33 + \frac{1}{5} = 33\frac{1}{5} \)
30) \( 81\frac{2}{14} - 63\frac{7}{14} = (81 - 63) + (\frac{2}{14} - \frac{7}{14}) = 18 - \frac{5}{14} = 17\frac{9}{14} \)
Столбик «5»
\( 1\frac{11}{12} + 2\frac{10}{12} = (1 + 2) + (\frac{11}{12} + \frac{10}{12}) = 3 + \frac{21}{12} = 3 + 1\frac{9}{12} = 4\frac{3}{4} \)
\( 9\frac{2}{3} + 11\frac{2}{3} = (9 + 11) + (\frac{2}{3} + \frac{2}{3}) = 20 + \frac{4}{3} = 20 + 1\frac{1}{3} = 21\frac{1}{3} \)
\( 6\frac{5}{6} + 3\frac{4}{6} = (6 + 3) + (\frac{5}{6} + \frac{4}{6}) = 9 + \frac{9}{6} = 9 + 1\frac{3}{6} = 10\frac{1}{2} \)
\( 4\frac{7}{9} + 7\frac{8}{9} = (4 + 7) + (\frac{7}{9} + \frac{8}{9}) = 11 + \frac{15}{9} = 11 + 1\frac{6}{9} = 12\frac{2}{3} \)
\( 8\frac{4}{10} + 6\frac{9}{10} = (8 + 6) + (\frac{4}{10} + \frac{9}{10}) = 14 + \frac{13}{10} = 14 + 1\frac{3}{10} = 15\frac{3}{10} \)
\( 10\frac{32}{33} + 11\frac{12}{33} = (10 + 11) + (\frac{32}{33} + \frac{12}{33}) = 21 + \frac{44}{33} = 21 + 1\frac{11}{33} = 22\frac{1}{3} \)
\( 12\frac{3}{16} + 33\frac{15}{16} = (12 + 33) + (\frac{3}{16} + \frac{15}{16}) = 45 + \frac{18}{16} = 45 + 1\frac{2}{16} = 46\frac{1}{8} \)
\( 4\frac{19}{21} + 9\frac{20}{21} = (4 + 9) + (\frac{19}{21} + \frac{20}{21}) = 13 + \frac{39}{21} = 13 + 1\frac{18}{21} = 14\frac{6}{7} \)
\( 15\frac{54}{55} + 51\frac{41}{55} = (15 + 51) + (\frac{54}{55} + \frac{41}{55}) = 66 + \frac{95}{55} = 66 + 1\frac{40}{55} = 67\frac{8}{11} \)
Ответ: Результаты вычислений выше.
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