Вопрос:

Ответ:

\[\sin\alpha = \frac{1}{2};\ \cos\alpha = \frac{\sqrt{3}}{2}\]

\[\sin\beta = \frac{1}{2};\ \cos\beta = - \frac{\sqrt{3}}{2}\]

\[\sin\gamma = - \frac{1}{2};\ \cos\gamma = - \frac{\sqrt{3}}{2}\]

\[\sin\varphi = - \frac{1}{2};\ \cos\varphi = \frac{\sqrt{3}}{2}\]