Найди корень уравнения (c+4)/6=(3c-2)/7.

\[\frac{c + 4}{6} = \frac{3c - 2}{7}\]

\[7 \cdot (c + 4) = 6 \cdot (3c - 2)\]

\[7c + 28 = 18c - 12\]

\[18c - 7c = 28 + 12\]

\[11c = 40\]

\[c = 40\ :11\]

\[c = 3\frac{7}{11}.\]