Решение заданий на сложение и вычитание дробей

Столбец A

1. 
   
\(\frac{1}{3}\) + \(\frac{1}{6}\) = \(\frac{2}{6}\) + \(\frac{1}{6}\) = \(\frac{3}{6}\) = \(\frac{1}{2}\)

   


2. 
   
\(\frac{1}{2}\) + \(\frac{1}{3}\) = \(\frac{3}{6}\) + \(\frac{2}{6}\) = \(\frac{5}{6}\)

   


3. 
   
\(\frac{3}{5}\) - \(\frac{1}{10}\) = \(\frac{6}{10}\) - \(\frac{1}{10}\) = \(\frac{5}{10}\) = \(\frac{1}{2}\)

   


4. 
   
\(\frac{1}{12}\) + \(\frac{5}{6}\) = \(\frac{1}{12}\) + \(\frac{10}{12}\) = \(\frac{11}{12}\)

   


5. 
   
\(\frac{1}{3}\) + \(\frac{1}{4}\) = \(\frac{4}{12}\) + \(\frac{3}{12}\) = \(\frac{7}{12}\)

   


6. 
   
\(\frac{1}{3}\) + \(\frac{2}{5}\) = \(\frac{5}{15}\) + \(\frac{6}{15}\) = \(\frac{11}{15}\)

   


7. 
   
\(\frac{1}{2}\) - \(\frac{1}{4}\) = \(\frac{2}{4}\) - \(\frac{1}{4}\) = \(\frac{1}{4}\)

   


8. 
   
\(\frac{8}{7}\) - 1 = \(\frac{8}{7}\) - \(\frac{7}{7}\) = \(\frac{1}{7}\)

   


9. 
   
\(\frac{1}{4}\) - \(\frac{1}{5}\) = \(\frac{5}{20}\) - \(\frac{4}{20}\) = \(\frac{1}{20}\)

   


10. 
    
\(\frac{1}{2}\) + \(\frac{3}{7}\) = \(\frac{7}{14}\) + \(\frac{6}{14}\) = \(\frac{13}{14}\)

    

Столбец Б

1. 
   
\(\frac{1}{3}\) - \(\frac{1}{6}\) = \(\frac{2}{6}\) - \(\frac{1}{6}\) = \(\frac{1}{6}\)

   


2. 
   
\(\frac{3}{20}\) + \(\frac{3}{4}\) = \(\frac{3}{20}\) + \(\frac{15}{20}\) = \(\frac{18}{20}\) = \(\frac{9}{10}\)

   


3. 
   
\(\frac{7}{9}\) - \(\frac{2}{3}\) = \(\frac{7}{9}\) - \(\frac{6}{9}\) = \(\frac{1}{9}\)

   


4. 
   
\(\frac{1}{4}\) + \(\frac{1}{5}\) = \(\frac{5}{20}\) + \(\frac{4}{20}\) = \(\frac{9}{20}\)

   


5. 
   
\(\frac{2}{5}\) + \(\frac{4}{15}\) = \(\frac{6}{15}\) + \(\frac{4}{15}\) = \(\frac{10}{15}\) = \(\frac{2}{3}\)

   


6. 
   
\(\frac{1}{3}\) + \(\frac{1}{4}\) = \(\frac{4}{12}\) + \(\frac{3}{12}\) = \(\frac{7}{12}\)

   


7. 
   
\(\frac{2}{3}\) - \(\frac{2}{5}\) = \(\frac{10}{15}\) - \(\frac{6}{15}\) = \(\frac{4}{15}\)

   


8. 
   
\(\frac{1}{5}\) - \(\frac{1}{6}\) = \(\frac{6}{30}\) - \(\frac{5}{30}\) = \(\frac{1}{30}\)

   


9. 
   
\(\frac{1}{2}\) + \(\frac{1}{4}\) = \(\frac{2}{4}\) + \(\frac{1}{4}\) = \(\frac{3}{4}\)

   


10. 
    
\(\frac{7}{6}\) - 1 = \(\frac{7}{6}\) - \(\frac{6}{6}\) = \(\frac{1}{6}\)