Найдите корень уравнения (x+2)/9=(x-3)/2.

\[\frac{x + 2}{9} = \frac{x - 3}{2}\]

\[2 \cdot (x + 2) = 9 \cdot (x - 3)\]

\[2x + 4 = 9x - 27\]

\[9x - 2x = 4 + 27\]

\[7x = 31\]

\[x = \frac{31}{7}\]

\[x = 4\frac{3}{7}\text{.\ }\]