Найдите корни уравнения: (2,5y-4)(6y+1,8)=0.

\[(2,5y - 4)(6y + 1,8) = 0\]

\[1)\ 2,5y - 4 = 0\]

\[2,5y = 4\]

\[y = \frac{4}{2,5} = \frac{40}{25} = \frac{8}{5}\]

\[y = 1,6.\]

\[2)\ 6y + 1,8 = 0\]

\[6y = - 1,8\]

\[y = - \frac{1,8}{6}\]

\[y = - 0,3.\]

\[Ответ:y = - 0,3;y = 1,6.\]