Найдите множество решений неравенства: (6-x)(3x+12)<=0.

\[(6 - x)(3x + 12) \leq 0\]

\[- 3(x - 6)(x + 4) \leq 0\]

\[(x + 4)(x - 6) \geq 0\]

\[x \leq - 4;\ \ x \geq 6.\]