Вопрос:

Ответ:

\[y = \sqrt{4x - x^{2}}\]

\[4x - x^{2} \geq 0\]

\[x^{2} - 4x \leq 0\]

\[x(x - 4) \leq 0\]

\[0 \leq x \leq 4.\]