\[\frac{1}{R_{12}} = \frac{1}{R_1} + \frac{1}{R_2} = \frac{1}{2} + \frac{1}{8} = \frac{4}{8} + \frac{1}{8} = \frac{5}{8}\]
\[R_{12} = \frac{8}{5} = 1.6 \,\text{Ом}\]
\[\frac{1}{R_{34}} = \frac{1}{R_3} + \frac{1}{R_4} = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}\]
\[R_{34} = 2 \,\text{Ом}\]
\[R_{общ} = R_{12} + R_{34} + R_5 = 1.6 + 2 + 3.4 = 7 \,\text{Ом}\]
\[I_{общ} = \frac{U_{R5}}{R_5} = \frac{68}{3.4} = 20 \,\text{А}\]
\[U_{12} = I_{общ} \cdot R_{12} = 20 \cdot 1.6 = 32 \,\text{В}\]
\[U_{34} = I_{общ} \cdot R_{34} = 20 \cdot 2 = 40 \,\text{В}\]
\[I_1 = \frac{U_{12}}{R_1} = \frac{32}{2} = 16 \,\text{А}\]
\[I_2 = \frac{U_{12}}{R_2} = \frac{32}{8} = 4 \,\text{А}\]
\[I_3 = \frac{U_{34}}{R_3} = \frac{40}{3} = 13.33 \,\text{А}\]
\[I_4 = \frac{U_{34}}{R_4} = \frac{40}{6} = 6.67 \,\text{А}\]
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