Найдите разность: 1) 7 5/6 − 3 2/3; 3) 11 11/12 − 5 7/9; 4) 9 17/24 − 8 11/36.

1. \(7\frac{5}{6}-3\frac{2}{3}=4+\left(\frac{5}{6}-\frac{4}{6}\right)=4\frac{1}{6}\).
2. \(11\frac{11}{12}-5\frac{7}{9}=6+\left(\frac{33}{36}-\frac{28}{36}\right)=6\frac{5}{36}\).
3. \(9\frac{17}{24}-8\frac{11}{36}=1+\left(\frac{51}{72}-\frac{22}{72}\right)=1\frac{29}{72}\).

Ответ: 1) \(4\frac{1}{6}\); 3) \(6\frac{5}{36}\); 4) \(1\frac{29}{72}\).