Решение

• a) $$1-\frac{4}{17} = \frac{17}{17} - \frac{4}{17} = \frac{17-4}{17} = \frac{13}{17}$$
• б) $$5-\frac{7}{13} = \frac{5 \cdot 13}{13} - \frac{7}{13} = \frac{65}{13} - \frac{7}{13} = \frac{65-7}{13} = \frac{58}{13} = 4\frac{6}{13}$$
• в) $$6-5\frac{6}{11} = 6 - \frac{5 \cdot 11 + 6}{11} = 6 - \frac{55+6}{11} = 6 - \frac{61}{11} = \frac{6 \cdot 11}{11} - \frac{61}{11} = \frac{66}{11} - \frac{61}{11} = \frac{66-61}{11} = \frac{5}{11}$$
• г) $$4\frac{5}{9}-3 = 4 + \frac{5}{9} - 3 = (4-3) + \frac{5}{9} = 1 + \frac{5}{9} = 1\frac{5}{9}$$

Ответ: a) $$\frac{13}{17}$$; б) $$4\frac{6}{13}$$; в) $$\frac{5}{11}$$; г) $$1\frac{5}{9}$$