Найдите сумму: $$3\frac{5}{8}+4\frac{1}{24}=$$ $$4\frac{10}{75}+6\frac{45}{14}=$$ $$4\frac{7}{14}+1\frac{8}{27}=$$ $$54\frac{3}{4}+18\frac{5}{6}=$$ Найдите разность: $$7-\frac{4}{17}=$$ $$5-\frac{13}{17}=$$ $$6-5\frac{5}{6}=$$ $$4\frac{8}{9}-3=$$

$$\begin{aligned}3\frac{5}{8}+4\frac{1}{24}&=3\frac{15}{24}+4\frac{1}{24}=7\frac{16}{24}=7\frac{2}{3}\\4\frac{10}{75}+6\frac{45}{14}&=\text{Нельзя выполнить сложение, т.к. дробная часть больше 1}\\4\frac{7}{14}+1\frac{8}{27}&=4\frac{1}{2}+1\frac{8}{27}=4\frac{27}{54}+1\frac{16}{54}=5\frac{43}{54}\\54\frac{3}{4}+18\frac{5}{6}&=54\frac{9}{12}+18\frac{10}{12}=72\frac{19}{12}=73\frac{7}{12}\\7-\frac{4}{17}&=6\frac{17}{17}-\frac{4}{17}=6\frac{13}{17}\\5-\frac{13}{17}&=4\frac{17}{17}-\frac{13}{17}=4\frac{4}{17}\\6-5\frac{5}{6}&=5\frac{6}{6}-5\frac{5}{6}=\frac{1}{6}\\4\frac{8}{9}-3&=1\frac{8}{9}\end{aligned}$$