8. Найдите значение дроби: $$\frac{2\frac{7}{9} \cdot (-5\frac{5}{7} + 2,1)}{-1\frac{1}{9} - 1\frac{2}{3}}$$

$$\frac{2\frac{7}{9} \cdot (-5\frac{5}{7} + 2,1)}{-1\frac{1}{9} - 1\frac{2}{3}} = \frac{\frac{25}{9} \cdot (-\frac{40}{7} + \frac{21}{10})}{-\frac{10}{9} - \frac{5}{3}} = \frac{\frac{25}{9} \cdot (\frac{-400+147}{70})}{\frac{-10-15}{9}} = \frac{\frac{25}{9} \cdot (\frac{-253}{70})}{\frac{-25}{9}} = \frac{\frac{25}{9} \cdot (\frac{-253}{70})}{\frac{-25}{9}} = \frac{25}{9} \cdot \frac{-253}{70} \cdot \frac{9}{-25} = \frac{-253}{70} \cdot (-1) = \frac{253}{70} = \frac{36\frac{1}{7}}{10} = 3,614... \approx 3.61$$ $$\frac{\frac{25}{9} \cdot (\frac{-253}{70})}{\frac{-25}{9}} = \frac{25}{9} \cdot \frac{-253}{70} \cdot \frac{9}{-25} = \frac{-253}{-70} = \frac{253}{70}$$