a) (-0.125y^4) при (y = -2):
(-0.125 cdot (-2)^4 = -0.125 cdot 16 = -2).
б) (12x^2y) при (x = -0.3, y = \frac{1}{6}):
(12 cdot (-0.3)^2 cdot \frac{1}{6} = 12 cdot 0.09 cdot \frac{1}{6} = 12 cdot \frac{9}{100} cdot \frac{1}{6} = \frac{12}{6} cdot \frac{9}{100} = 2 cdot \frac{9}{100} = \frac{18}{100} = 0.18).