1) \(\frac{5}{11} \cdot \frac{6}{25}\) = \(\frac{5 \cdot 6}{11 \cdot 25}\) = \(\frac{1 \cdot 6}{11 \cdot 5}\) = \(\frac{6}{55}\)
2) \(1\frac{9}{11} \cdot \frac{2}{3}\) = \(\frac{20}{11} \cdot \frac{2}{3}\) = \(\frac{20 \cdot 2}{11 \cdot 3}\) = \(\frac{40}{33}\)
3) \(2\frac{5}{14} - \frac{6}{55} - \frac{40}{33}\) = \(\frac{33}{14} - \frac{6}{55} - \frac{40}{33}\) = \(\frac{33 \cdot 165 - 6 \cdot 42 - 40 \cdot 70}{2310}\) = \(\frac{5445 - 252 - 2800}{2310}\) = \(\frac{2393}{2310}\) = \(1\frac{83}{2310}\)
Ответ: \(1\frac{83}{2310}\)