Решение:

1) $$(2\frac{13}{48} - (-2\frac{5}{12})) \cdot (-3\frac{3}{4}) + 9\frac{3}{4} : (-13)$$

1. $$2\frac{13}{48} + 2\frac{5}{12} = 2\frac{13}{48} + 2\frac{20}{48} = 4\frac{33}{48} = 4\frac{11}{16} = \frac{4\cdot16 + 11}{16} = \frac{64+11}{16} = \frac{75}{16}$$
2. $$\frac{75}{16} \cdot (-3\frac{3}{4}) = \frac{75}{16} \cdot (-\frac{15}{4}) = -\frac{75\cdot15}{16\cdot4} = -\frac{1125}{64}$$
3. $$9\frac{3}{4} : (-13) = \frac{39}{4} : (-13) = \frac{39}{4} \cdot (-\frac{1}{13}) = -\frac{39}{4\cdot13} = -\frac{3}{4}$$
4. $$-\frac{1125}{64} - \frac{3}{4} = -\frac{1125}{64} - \frac{48}{64} = -\frac{1125 + 48}{64} = -\frac{1173}{64} = -18\frac{21}{64}$$

Ответ: $$-18\frac{21}{64}$$

2) $$(1\frac{2}{3} - 3,6) : (-2\frac{7}{9} + 4\frac{1}{15}) \cdot (-2,6)$$

1. $$1\frac{2}{3} - 3,6 = \frac{5}{3} - \frac{36}{10} = \frac{5}{3} - \frac{18}{5} = \frac{25 - 54}{15} = \frac{-29}{15}$$
2. $$-2\frac{7}{9} + 4\frac{1}{15} = -\frac{25}{9} + \frac{61}{15} = \frac{-25\cdot5 + 61\cdot3}{45} = \frac{-125 + 183}{45} = \frac{58}{45}$$
3. $$\frac{-29}{15} : \frac{58}{45} = \frac{-29}{15} \cdot \frac{45}{58} = \frac{-1}{1} \cdot \frac{3}{2} = -\frac{3}{2} = -1,5$$
4. $$-1,5 \cdot (-2,6) = 3,9$$

Ответ: $$3,9$$