Краткое пояснение: Применим формулу разности квадратов: \( (a - b)(a + b) = a^2 - b^2 \).
Решения:
- 80: \( (2\sqrt{8})^2 = 4 * 8 = 32 \)
- 81: \( (\sqrt{19} - \sqrt{2})(\sqrt{19} + \sqrt{2}) = 19 - 2 = 17 \)
- 82: \( (\sqrt{7} - \sqrt{2})(\sqrt{7} + \sqrt{2}) = 7 - 2 = 5 \)
- 83: \( (\sqrt{5} - \sqrt{2})(\sqrt{5} + \sqrt{2}) = 5 - 2 = 3 \)
- 84: \( (\sqrt{19} - \sqrt{5})(\sqrt{19} + \sqrt{5}) = 19 - 5 = 14 \)
- 85: \( (\sqrt{5} - \sqrt{3})(\sqrt{5} + \sqrt{3}) = 5 - 3 = 2 \)
- 86: \( (\sqrt{17} - \sqrt{5})(\sqrt{17} + \sqrt{5}) = 17 - 5 = 12 \)
- 87: \( (\sqrt{17} - \sqrt{3})(\sqrt{17} + \sqrt{3}) = 17 - 3 = 14 \)
- 88: \( (\sqrt{13} - \sqrt{2})(\sqrt{13} + \sqrt{2}) = 13 - 2 = 11 \)
- 89: \( (\sqrt{7} - \sqrt{5})(\sqrt{7} + \sqrt{5}) = 7 - 5 = 2 \)
- 90: \( (\sqrt{7} - \sqrt{3})(\sqrt{7} + \sqrt{3}) = 7 - 3 = 4 \)
- 91: \( (\sqrt{31} - 3)(\sqrt{31} + 3) = 31 - 9 = 22 \)
- 92: \( (\sqrt{41} - 3)(\sqrt{41} + 3) = 41 - 9 = 32 \)
- 93: \( (\sqrt{37} - 5)(\sqrt{37} + 5) = 37 - 25 = 12 \)