Разбираемся:
\( 6 \cdot (\frac{1}{3})^2 - 17 \cdot \frac{1}{3} = 6 \cdot \frac{1}{9} - \frac{17}{3} = \frac{6}{9} - \frac{17}{3} = \frac{2}{3} - \frac{17}{3} = \frac{2-17}{3} = \frac{-15}{3} = -5 \)
\( 9 \cdot (\frac{1}{9})^2 - 19 \cdot \frac{1}{9} = 9 \cdot \frac{1}{81} - \frac{19}{9} = \frac{9}{81} - \frac{19}{9} = \frac{1}{9} - \frac{19}{9} = \frac{1-19}{9} = \frac{-18}{9} = -2 \)
\( 10 \cdot (\frac{1}{5})^2 - 12 \cdot \frac{1}{5} = 10 \cdot \frac{1}{25} - \frac{12}{5} = \frac{10}{25} - \frac{12}{5} = \frac{2}{5} - \frac{12}{5} = \frac{2-12}{5} = \frac{-10}{5} = -2 \)
\( 14 \cdot (\frac{1}{7})^2 - 23 \cdot \frac{1}{7} = 14 \cdot \frac{1}{49} - \frac{23}{7} = \frac{14}{49} - \frac{23}{7} = \frac{2}{7} - \frac{23}{7} = \frac{2-23}{7} = \frac{-21}{7} = -3 \)
\( 21 \cdot (\frac{1}{7})^2 - 10 \cdot \frac{1}{7} = 21 \cdot \frac{1}{49} - \frac{10}{7} = \frac{21}{49} - \frac{10}{7} = \frac{3}{7} - \frac{10}{7} = \frac{3-10}{7} = \frac{-7}{7} = -1 \)
\( 8 \cdot (\frac{1}{4})^2 - 14 \cdot \frac{1}{4} = 8 \cdot \frac{1}{16} - \frac{14}{4} = \frac{8}{16} - \frac{14}{4} = \frac{1}{2} - \frac{14}{4} = \frac{2}{4} - \frac{14}{4} = \frac{2-14}{4} = \frac{-12}{4} = -3 \)
\( 45 \cdot (\frac{1}{9})^2 - 14 \cdot \frac{1}{9} = 45 \cdot \frac{1}{81} - \frac{14}{9} = \frac{45}{81} - \frac{14}{9} = \frac{5}{9} - \frac{14}{9} = \frac{5-14}{9} = \frac{-9}{9} = -1 \)
Ответы: