Ответ:
- \(18\cdot\left(\frac{1}{9}\right)^2-20\cdot\frac{1}{9}=18\cdot\frac{1}{81}-\frac{20}{9}=\frac{2}{9}-\frac{20}{9}=-2\).
- \(\frac{2}{25}+\frac{1}{4}=\frac{8}{100}+\frac{25}{100}=\frac{33}{100}\).
- \(\frac{3}{4}-\frac{9}{8}=\frac{6}{8}-\frac{9}{8}=-\frac{3}{8}\).
- \(\frac{1}{\frac{1}{30}+\frac{1}{42}}=\frac{1}{\frac{7}{210}+\frac{5}{210}}=\frac{1}{\frac{12}{210}}=\frac{35}{2}\).
- \(\left(1\frac{11}{16}-3\frac{7}{8}\right)\cdot4=\left(\frac{27}{16}-\frac{62}{16}\right)\cdot4=-\frac{35}{16}\cdot4=-\frac{35}{4}\).
- \(\left(\frac{5}{6}+\frac{7}{15}\right)\cdot3=\left(\frac{25}{30}+\frac{14}{30}\right)\cdot3=\frac{39}{30}\cdot3=\frac{39}{10}\).
- \(\frac{1.5}{1+\frac{1}{5}}=\frac{\frac{3}{2}}{\frac{6}{5}}=\frac{3}{2}\cdot\frac{5}{6}=\frac{5}{4}\).
- \(\frac{1}{4}+\frac{37}{20}=\frac{5}{20}+\frac{37}{20}=\frac{42}{20}=\frac{21}{10}\).
- \(\frac{1}{10}-\frac{35}{50}=\frac{5}{50}-\frac{35}{50}=-\frac{30}{50}=-\frac{3}{5}\).
- \(\frac{9}{5}:\frac{2}{3}=\frac{9}{5}\cdot\frac{3}{2}=\frac{27}{10}\).
- \(\frac{6}{5}:\frac{4}{11}=\frac{6}{5}\cdot\frac{11}{4}=\frac{33}{10}\).
- \(\frac{6}{5\cdot4}=\frac{6}{20}=\frac{3}{10}\).
Ответ: 1) −2; 2) \(\frac{33}{100}\); 3) \(-\frac{3}{8}\); 4) \(\frac{35}{2}\); 5) \(-\frac{35}{4}\); 6) \(\frac{39}{10}\); 7) \(\frac{5}{4}\); 8) \(\frac{21}{10}\); 9) \(-\frac{3}{5}\); 10) \(\frac{27}{10}\); 11) \(\frac{33}{10}\); 12) \(\frac{3}{10}\).
