\[ \frac{2}{9} + \frac{1}{4} = \frac{2 \times 4}{9 \times 4} + \frac{1 \times 9}{4 \times 9} = \frac{8}{36} + \frac{9}{36} = \frac{8+9}{36} = \frac{17}{36} \]
\[ \frac{17}{9} : \frac{17}{36} = \frac{17}{9} \times \frac{36}{17} \]
\[ \frac{\cancel{17}}{\cancel{9}} \times \frac{\cancel{36}^4}{\cancel{17}} = \frac{1}{1} \times \frac{4}{1} = 4 \]
Ответ: 4