Ответ:

Преобразуем смешанные числа в неправильные дроби:

\(1{,}6=\frac{8}{5},\quad 1\frac{14}{15}=\frac{29}{15},\quad 1\frac{11}{21}=\frac{32}{21}.\)

\[3-\left(\frac{8}{5}-\frac{29}{15}\right)\cdot\frac{6}{7}:\frac{32}{21}=3-\left(\frac{24}{15}-\frac{29}{15}\right)\cdot\frac{6}{7}\cdot\frac{21}{32}.\]

\[=3-\left(-\frac{1}{3}\right)\cdot\frac{6}{7}\cdot\frac{21}{32}=3+\frac{9}{16}=3\frac{9}{16}.\]

Ответ: \(3\frac{9}{16}\).