Ответ:
\[55\cdot\left(\frac{2}{11}\right)^2+12\cdot\frac{2}{11}=55\cdot\frac{4}{121}+\frac{24}{11}=\frac{220}{121}+\frac{264}{121}=\frac{484}{121}=4.\]
Ответ: 4.
\[55\cdot\left(\frac{2}{11}\right)^2+12\cdot\frac{2}{11}=55\cdot\frac{4}{121}+\frac{24}{11}=\frac{220}{121}+\frac{264}{121}=\frac{484}{121}=4.\]
Ответ: 4.