Заполним таблицу, подставляя значения переменной b в выражения.
| № | Выражение | b = -3 | b = -1 | b = 0 | b = 2 |
| 1) | b - 1 | \( -3 - 1 = -4 \) | \( -1 - 1 = -2 \) | \( 0 - 1 = -1 \) | \( 2 - 1 = 1 \) |
| 2) | 1 - b | \( 1 - (-3) = 1 + 3 = 4 \) | \( 1 - (-1) = 1 + 1 = 2 \) | \( 1 - 0 = 1 \) | \( 1 - 2 = -1 \) |
| 3) | 1 - b2 | \( 1 - (-3)^2 = 1 - 9 = -8 \) | \( 1 - (-1)^2 = 1 - 1 = 0 \) | \( 1 - 0^2 = 1 - 0 = 1 \) | \( 1 - 2^2 = 1 - 4 = -3 \) |
| 4) | b2 - 1 | \( (-3)^2 - 1 = 9 - 1 = 8 \) | \( (-1)^2 - 1 = 1 - 1 = 0 \) | \( 0^2 - 1 = 0 - 1 = -1 \) | \( 2^2 - 1 = 4 - 1 = 3 \) |
| 5) | 1 - b3 | \( 1 - (-3)^3 = 1 - (-27) = 1 + 27 = 28 \) | \( 1 - (-1)^3 = 1 - (-1) = 1 + 1 = 2 \) | \( 1 - 0^3 = 1 - 0 = 1 \) | \( 1 - 2^3 = 1 - 8 = -7 \) |
| 6) | 2b - 1 | \( 2(-3) - 1 = -6 - 1 = -7 \) | \( 2(-1) - 1 = -2 - 1 = -3 \) | \( 2(0) - 1 = 0 - 1 = -1 \) | \( 2(2) - 1 = 4 - 1 = 3 \) |
| 7) | 2 - b | \( 2 - (-3) = 2 + 3 = 5 \) | \( 2 - (-1) = 2 + 1 = 3 \) | \( 2 - 0 = 2 \) | \( 2 - 2 = 0 \) |
| 8) | (1 - b)2 | \( (1 - (-3))^2 = (1 + 3)^2 = 4^2 = 16 \) | \( (1 - (-1))^2 = (1 + 1)^2 = 2^2 = 4 \) | \( (1 - 0)^2 = 1^2 = 1 \) | \( (1 - 2)^2 = (-1)^2 = 1 \) |
Ответ: таблица заполнена выше.