Найдите значение выражения: a) $$\frac{3}{14} + (\frac{2}{7} + \frac{1}{2})$$; б) $$\frac{11}{56} + (\frac{6}{7} - \frac{3}{8})$$; в) $$(\frac{5}{8} + \frac{1}{6}) - \frac{7}{24}$$

Решаем примеры:

a) $$\frac{3}{14} + (\frac{2}{7} + \frac{1}{2}) = \frac{3}{14} + (\frac{2 \cdot 2}{7 \cdot 2} + \frac{1 \cdot 7}{2 \cdot 7}) = \frac{3}{14} + (\frac{4}{14} + \frac{7}{14}) = \frac{3}{14} + \frac{11}{14} = \frac{3+11}{14} = \frac{14}{14} = 1$$

б) $$\frac{11}{56} + (\frac{6}{7} - \frac{3}{8}) = \frac{11}{56} + (\frac{6 \cdot 8}{7 \cdot 8} - \frac{3 \cdot 7}{8 \cdot 7}) = \frac{11}{56} + (\frac{48}{56} - \frac{21}{56}) = \frac{11}{56} + \frac{27}{56} = \frac{11+27}{56} = \frac{38}{56} = \frac{19}{28}$$

в) $$(\frac{5}{8} + \frac{1}{6}) - \frac{7}{24} = (\frac{5 \cdot 3}{8 \cdot 3} + \frac{1 \cdot 4}{6 \cdot 4}) - \frac{7}{24} = (\frac{15}{24} + \frac{4}{24}) - \frac{7}{24} = \frac{19}{24} - \frac{7}{24} = \frac{19-7}{24} = \frac{12}{24} = \frac{1}{2}$$

Ответы: a) $$1$$; б) $$\frac{19}{28}$$; в) $$\frac{1}{2}$$