а)
$$
1 \frac{7}{32} \cdot (7 - 4 \frac{1}{3}) = \frac{1 \cdot 32 + 7}{32} \cdot (\frac{7}{1} - \frac{4 \cdot 3 + 1}{3}) = \frac{32 + 7}{32} \cdot (\frac{7}{1} - \frac{12 + 1}{3}) = \frac{39}{32} \cdot (\frac{7}{1} - \frac{13}{3}) = \frac{39}{32} \cdot (\frac{7 \cdot 3}{1 \cdot 3} - \frac{13}{3}) = \frac{39}{32} \cdot (\frac{21}{3} - \frac{13}{3}) = \frac{39}{32} \cdot \frac{21 - 13}{3} = \frac{39}{32} \cdot \frac{8}{3} = \frac{13}{4} \cdot \frac{1}{1} = \frac{13}{4} = 3 \frac{1}{4}
$$
б)
$$
(9,1 : 1,4 - 5,05) \cdot 1,2 = (9,1 : 1,4 - 5,05) \cdot 1,2 = (\frac{91}{10} : \frac{14}{10} - \frac{505}{100}) \cdot \frac{12}{10} = (\frac{91}{10} \cdot \frac{10}{14} - \frac{101}{20}) \cdot \frac{6}{5} = (\frac{13}{2} - \frac{101}{20}) \cdot \frac{6}{5} = (\frac{13 \cdot 10}{2 \cdot 10} - \frac{101}{20}) \cdot \frac{6}{5} = (\frac{130}{20} - \frac{101}{20}) \cdot \frac{6}{5} = \frac{130 - 101}{20} \cdot \frac{6}{5} = \frac{29}{20} \cdot \frac{6}{5} = \frac{29}{10} \cdot \frac{3}{5} = \frac{87}{50} = 1 \frac{37}{50}
$$
Ответ: a) $$3 \frac{1}{4}$$, б) $$1 \frac{37}{50}$$