a) $$3\frac{5}{16}+\frac{1}{4}-2\frac{1}{16} = 3\frac{5}{16}+\frac{4}{16}-2\frac{1}{16} = (3-2)+\frac{5+4-1}{16} = 1 + \frac{8}{16} = 1 \frac{1}{2}$$
Ответ: $$1 \frac{1}{2}$$
в) $$6\frac{11}{12}-3\frac{1}{6}-1\frac{1}{4} = 6\frac{11}{12}-3\frac{2}{12}-1\frac{3}{12} = (6-3-1)+\frac{11-2-3}{12} = 2 + \frac{6}{12} = 2 \frac{1}{2}$$
Ответ: $$2 \frac{1}{2}$$
г) $$3\frac{7}{9}-1\frac{5}{18}+3\frac{1}{2} = 3\frac{14}{18}-1\frac{5}{18}+3\frac{9}{18} = (3-1+3)+\frac{14-5+9}{18} = 5 + \frac{18}{18} = 6$$
Ответ: $$6$$
б) $$\frac{1}{8}+2\frac{3}{5}+2\frac{7}{8} = \frac{1}{8}+2\frac{3}{5}+2\frac{7}{8} = (2+2) + (\frac{1}{8}+\frac{7}{8}) + \frac{3}{5} = 4 + \frac{8}{8} + \frac{3}{5} = 4+1+\frac{3}{5} = 5\frac{3}{5}$$
Ответ: $$5\frac{3}{5}$$