3. a)
\[\sin 60^\circ = \frac{\sqrt{3}}{2}\]
\[\cos 30^\circ = \frac{\sqrt{3}}{2}\]
Тогда
\[\sin 60^\circ \cdot \cos 30^\circ + \frac{1}{4} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{1}{4} = \frac{3}{4} + \frac{1}{4} = 1\]
3. б)
\[\cos 30^\circ = \frac{\sqrt{3}}{2}\]
\[\cos^2 30^\circ = \left( \frac{\sqrt{3}}{2} \right)^2 = \frac{3}{4}\]
Тогда
\[4 \cos^2 30^\circ - 1 = 4 \cdot \frac{3}{4} - 1 = 3 - 1 = 2\]
Ответ: a) 1, б) 2