Ответ:

  1. \(\frac{7!-5!}{4!}=\frac{5040-120}{24}=\frac{4920}{24}=205\).

  2. \(\frac{7!}{5!}=\frac{7\cdot6\cdot5!}{5!}=42\).

  3. \((0!+5!)\cdot3!=(1+120)\cdot6=726\).

Ответ: \(\frac{7!-5!}{4!}\) — 205; \(\frac{7!}{5!}\) — 42; \((0!+5!)\cdot3!\) — 726.