Решение

1) a) $$4\frac{1}{8}+6\frac{13}{35} = \frac{33}{8} + \frac{223}{35} = \frac{33 \cdot 35 + 223 \cdot 8}{8 \cdot 35} = \frac{1155 + 1784}{280} = \frac{2939}{280} = 10\frac{139}{280}$$.

Ответ: $$10\frac{139}{280}$$

2) a) $$2\frac{1}{3}-4\frac{1}{16} = \frac{7}{3} - \frac{65}{16} = \frac{7 \cdot 16 - 65 \cdot 3}{3 \cdot 16} = \frac{112 - 195}{48} = \frac{-83}{48} = -1\frac{35}{48}$$.

Ответ: $$-1\frac{35}{48}$$

3) a) $$\frac{5}{9}:\frac{10}{27} = -\frac{5}{9} \cdot \frac{27}{10} = -\frac{5 \cdot 27}{9 \cdot 10} = -\frac{135}{90} = -\frac{3}{2} = -1\frac{1}{2}$$.

Ответ: $$-1\frac{1}{2}$$