No5 Заполните пропуски: a) 22 +73 = 5 7 10 6) 6-+35= = 812 3 + + 10 10 7 10 + 24 + 6 )8+20-10+-10 45 г) 92+5= 27 д) 5+211 = 19 19 31 24 24 24 11 ж) 11 80--8--8 = 3 7 7 e) 1-- = 7 86-10 3)5-20-08-20-08 )3+6= 6 к) 52+711 13 13 ن 5=2 1)3-0-2-0-2 6 6 6 6 )9-20-08-20-08 32

1. а) 2\(\frac{2}{5}\) + 7\(\frac{3}{10}\) = \(\frac{22}{10}\) + \(\frac{73}{10}\) = \(\frac{95}{10}\) = 9\(\frac{5}{10}\) = 9\(\frac{1}{2}\)
2. б) 6\(\frac{7}{8}\) + 3\(\frac{5}{12}\) = \(\frac{55}{8}\) + \(\frac{41}{12}\) = \(\frac{165}{24}\) + \(\frac{82}{24}\) = \(\frac{247}{24}\) = 10\(\frac{7}{24}\)
3. в) 8\(\frac{1}{9}\) + 2\(\frac{3}{5}\) = 10 + \(\frac{1}{9}\) + \(\frac{3}{5}\) = 10 + \(\frac{5}{45}\) + \(\frac{27}{45}\) = 10 + \(\frac{32}{45}\) = 10\(\frac{32}{45}\)
4. г) 9\(\frac{2}{7}\) + 5 = 14\(\frac{2}{7}\)
5. д) 5 + 2\(\frac{11}{19}\) = 7\(\frac{11}{19}\)
6. e) 1 - \(\frac{3}{7}\) = \(\frac{7}{7}\) - \(\frac{3}{7}\) = \(\frac{4}{7}\)
7. ж) 8 - \(\frac{9}{11}\) = \(\frac{88}{11}\) - \(\frac{9}{11}\) = \(\frac{79}{11}\) = 7\(\frac{2}{11}\)
8. з) 5 - 2\(\frac{3}{5}\) = \(\frac{25}{5}\) - \(\frac{13}{5}\) = \(\frac{12}{5}\) = 2\(\frac{2}{5}\)
9. и) 3\(\frac{2}{9}\) + 6 = 9\(\frac{2}{9}\)
10. к) 5\(\frac{2}{13}\) + 7\(\frac{11}{13}\) = 12 + \(\frac{2}{13}\) + \(\frac{11}{13}\) = 12 + \(\frac{13}{13}\) = 13
11. л) 3 - \(\frac{5}{6}\) = 2\(\frac{6}{6}\) - \(\frac{5}{6}\) = 2\(\frac{1}{6}\)
12. м) 9 - 2\(\frac{8}{9}\) = 7\(\frac{9}{9}\) - \(\frac{8}{9}\) = 7\(\frac{1}{9}\)

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